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7 July, 08:43

Use the chart to multiply the binomial by the trinomial (y+3) (y^2-3y+9) What is the product? y3 + 27 y3 - 27 y3 - 6y2 + 27 y3 + 6y2 + 27

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  1. 7 July, 10:58
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    (y+3) (y^2-3y + 9) = (y+3) (y^2 + - 3y + 9) = (y) (y^2) + (y) (-3y) + (y) (9) + (3) (y^2) + (3) (-3y) + (3) (9) = y^3 - 3y^2 + 9y + 3y^2 - 9y + 27 = y^3+27
  2. 7 July, 11:00
    0
    (y+3) (y^2 - 3y + 9) = (y+3) (y^2 + - 3y + 9) = (y) (y^2) + (y) ( - 3y) + (y) (9) + (3) (y^2) + (3) ( - 3y) + (3) (9) = y^3 - 3 y^2 + 9y + 3 y^2 - 9y + 27 = y^3 + 27
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