What four consecutive odd integers have a sum of 336?

Call x is the first number.

The second is x+2

The third is x+4

The forth is x+6

=> x + (x+2) + (x+4) + (x+6) = 336

4x + 12 = 336

4x = 324

x = 81

=> the first is 81; the second is 83, the third is 85 and the forth is 87