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25 May, 18:20

I have 3 equations 9x+6, 2 (5x-3) and 5y+14 how do i solve for x?

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  1. 25 May, 21:41
    0
    Set the equation equal to zero.

    9x+6=0

    Subtract 6 from both sides

    9x = - 6

    Divide both sides by 9

    x=-6/9

    or - 2/3

    2 (5x-3) = 0

    Distribute

    10x-6=0

    add 6 to both sides

    10x=6

    Divide by 10 on both sides

    x=6/10 or 4/5

    5y+14=0

    -14 from both sides

    5y=-14

    divide both sides by 5

    y=-14/5

    or - 2 and 4/5
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