The area of a rectangle is 54 square feet. Find the length and the width of the rectangle if the length is 3 feet greater than the width

Let the width of the rectangle be x

width = x

length = x+3

Area = width times length

Area = x (x+3)

= x^2 + 3x

Area = 54

implies that

x^2 + 3x = 54

x^2 + 3x - 54=0

x^2 + 9x - 6x - 54 = 0

x (x+9) - 6 (x+9) = 0

(x+9) (x-6) = 0

x=6

The width is 6 feet and the length is 3 plus 6 or 9.