Ask Question
9 May, 04:21

When a complex number is in the denominator, why is it necessary to multiply by the conjugate?

+5
Answers (1)
  1. 9 May, 07:01
    0
    Here is the explanation.

    For the general complex number (a + bi), its conjugate is (a - bi).

    By definition, i² = - 1.

    Evaluate (a + bi) * (a - bi) to obtain

    (a + bi) * (a - bi) = a² - abi + abi - b²i²

    = a² - b² * (-1)

    = a² + b²

    This means that multiplying a complex number by its conjugate yields a real number.

    For this reason, it is customary to make the denominator of a complex rational expression into a real number, by multiplying the denominator by its conjugate.

    Of course, the numerator should also be multiplied by the same conjugate.

    Example:

    Simplify (2 - 3i) / (1 + 4i) into the form a + bi.

    The denominator is (1 + 4i) and its conjugate is (1 - 4i).

    Multiply the denominator by its conjugate to obtain

    (1 + 4i) * (1 - 4i) = 1² + 4² = 17.

    Also, multiply the numerator by the same conjugate to obtain

    (2 - 3i) * (1 - 4i) = 2 - 8i - 3i + (3i) * (4i)

    = 2 - 11i + 12*i²

    = 2 - 11i - 12

    = - 10 - 11i

    Therefore

    (2 - 3i) / (1 + 4i) = - (10 + 11i) / 17
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “When a complex number is in the denominator, why is it necessary to multiply by the conjugate? ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers