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3 April, 09:16

A restaurant offers a "Create Your Own Pizza" menu option. There are 3 types of meat, 6 types of vegetables, and 3 kinds of cheese. Customers may choose one meat, one vegetable, and one cheese. You decide to have the chef choose the toppings randomly. What is the probability that the chef will make a pizza with chicken, banana peppers, and ricotta cheese?

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  1. 3 April, 09:53
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    Multiply 3 times 6 times 3 to get the total number of choices.

    Since there can only be one meat, one vegetable, and one cheese, the chances are 1/54.
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