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1 June, 20:12

The perimeter of a rectangular is P = 2L + 2W. Solve for L if the perimeter is 220 ft and the length is 10 ft more than the width.

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  1. 1 June, 20:19
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    220 = 2 (10+x) + 2x

    220 = 20+2x+2x

    220 = 20+4x

    200 = 4x

    50 = x

    if L is 10 more than W and the width = 50, than the length (L) would be 60 ft.
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