Ask Question
11 February, 05:06

He polynomial of degree 5, p (x) p (x) has leading coefficient 1, has roots of multiplicity 2 at x = 4 x=4 and x = 0 x=0, and a root of multiplicity 1 at x = - 4 x=-4 find a possible formula for p (x) p (x).

+4
Answers (1)
  1. 11 February, 05:12
    0
    Root of x = 4 means (x - 4) is a factorMultiplicity of two means that (x - 4) is used twice root of x = - 4 means that (x + 4) is a factormultiplicity of 1 means it is used once so y = a (x-4) (x-4) (x + 4) y = a (x^3 - 4x2 - 16x + 64)

    Thus, any polynomial with these zeroans d as a minimum these multiplicities will be a multiple (scalar or polynomial) of this P (x).
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “He polynomial of degree 5, p (x) p (x) has leading coefficient 1, has roots of multiplicity 2 at x = 4 x=4 and x = 0 x=0, and a root of ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers