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10 February, 13:49

A force is specified by the vector f = (105i + 135j - 175k) n. calculate the angles made by f with the positive x-, y-, and z-axes.

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  1. 10 February, 17:04
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    Calculate the direction cosines, and hence find the angles.

    unit vector

    =/sqrt (105^2+135^2 + (-175) ^2)

    =

    = (approx.)

    Therefore the direction cosines are respectively

    0.4291,0.5517,-0.7152, and the angles with the x, y and z-axes are:

    acos (0.4291), acos (0.5517), acos (-0.7152)

    =64.59, 56.51, and 135.66 degrees respectively.
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