A cylinder has its height doubled and its radius cut to 1/3. What is the ratio of the volumes of the modified cylinder to the original cylinder

Let height of a cylinder is h and radius be r

volume of cylinder = πr*r*h

if height is doubled then height becomes = 2h

radius becomes one third = 1/3 r

volume of cylinder becomes = π*1/3r*1/3r*2h = 2/9πr*r*h

ratio of original cylinder to new one = 9/2

1 is to 4.5; the original cylinder was 3.14 and the modified cylinder was. 698

(I ignored units)