Solve these simultaneous equations:

5x+2y=24 and 4x+3y=10

From the second equation: y = (10-4x) / 3

Substitute y to the first equation:

5x+2[ (10-4x) / 3] = 24

5x+[ (20/3) - (8x/3) ]=24

5x - (8x/3) = 24 - (20/3)

(15x-8x) / 3=17.333

7x=17.333 (3)

x=7.428

Using the second equation to find value of y:

y = (10-4x) / 3; Substitute the value of x=7.428

y=[10-4 (7.428) ]/3

y = - 6.571 (negative 6.571)