Name the values of x and y so that the value of 5x+3 is greater than the value of 2y+14

X=6

y=1

y can be anything really low and x can be the opposite

5x + 3 > 2y + 14

Subtract 3 from each side: 5x > 2y + 11

Divide each side by 5 : x > 0.2 (2y + 11).

You can pick any number you want for 'y'.

Once you have that, 'x' has to be more than 20% of (2y + 11).

Another way to say it: 'x' must be more than (0.4 x + 2.2).