Given that f (x) = x 2+3x+6 and g (x) = x-3, solve for f (g (x)) when x=1

F (x) = x²+3x+6 and g (x) = x-3, to calculate f (g (x)), let's replace x in f (x) by

(x-3) in g (x):

f (g (x)) = (x-3) ² + 3 (x-3) + 6

f (g (x)) = x²-6x+9 + 3x-9 + 6

f (g (x)) = x²-3x+6,:

f (g (1)) = 1² - 3 (1) + 6:

f (g (1)) = 4