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31 December, 11:25

Given that f (x) = x 2+3x+6 and g (x) = x-3, solve for f (g (x)) when x=1

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  1. 31 December, 12:46
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    F (x) = x²+3x+6 and g (x) = x-3, to calculate f (g (x)), let's replace x in f (x) by

    (x-3) in g (x):

    f (g (x)) = (x-3) ² + 3 (x-3) + 6

    f (g (x)) = x²-6x+9 + 3x-9 + 6

    f (g (x)) = x²-3x+6,:

    f (g (1)) = 1² - 3 (1) + 6:

    f (g (1)) = 4
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