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20 April, 01:52

Calculate work of a man holding a barbell at chest hight 2 m for 15 seconds?

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  1. 20 April, 02:37
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    Answer: 0J

    The equation for work is W=Fdcos (x), where w=work, f=force, d=displacement, and x=angle the force makes with the displacement vector.

    Since the man is holding a barbell and the object, the barbell, isn't being displaced, d=0, making the work done equal to zero.
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