3x+4y=-23

2y-x=-19

What is the solution (x, y) to the systems of equations above?

If we multiply the bottom equation by 2 and move x to the right, it becomes:

4y = 2x-38

Now we can substitute it for the 4y in the top equation:

3x + (2x-38) = - 23 = > 5x = - 23+38 = > 5x = 15 = > x=3

Then 4y = 2*3-38 = > y = - 8

So the solution is (3,-8)