How many ways can a president, vice-president, secretary, and treasurer be chosen from a club with 9 members? assume that no member can hold more than one office?

Question

Mathematics

Finley Barber

23 April, 19:54

How many ways can a president, vice-president, secretary, and treasurer be chosen from a club with 9 members? assume that no member can hold more than one office?

+3

Answers (1)

Know the Answer?

Orion Coffey · Answer 1

This type of problem is a permutation problem. Permutation is the arrangement of a set with certain order. In the problem, if there are 9 members, and 3 positions are available without repeating, we can write the expression as 9P3 - 3 non repeating positions in a set of 9 elements. By evaluating, we will have 9! / (9-3) ! = 504. The answer is 504.