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12 January, 01:16

1. The center of a circle is located at (5, - 5). The radius of the circle is 3.

What is the equation of the circle in general form?

x^2+y^2+10x-10y+47=0

x^2+y^2+10x-10y+41=0

x^2+y^2-10x+10y+47=0

x^2+y^2-10x+10y+41=0

2. The standard form of the equation of a circle is (x-5) 2 + (y-6) 2=1.

What is the general form of the equation?

x^2+y^2-10x-12y-62=0

x^2+y^2+10x+12y+62=0

x^2+y^2-10x-12y+60=0

x^2+y^2+10x+12y+60=0

+4
Answers (1)
  1. 12 January, 05:14
    0
    Hello,

    1) Answer D since (x-5) ² + (y+5) ²=9 = = >x²+y²-10x+10y+41=0

    2) Answer C since (x-5) ² + (y-6) ²=1 = = >x²+y²-10x-12y+60=0
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