Consider the line = + 3x6y-8. what is the slope of a line parallel to this line? what is the slope of a line perpendicular to this line?

Two lines are parallel if their slope is the same.

You want to write 8x + 4y = 5 in the form y = mx + b, where m represents the slope and b is the y-intercept.

We need to isolate y in the given equation. The number next to x is the slope.

8x + 4y = 5

4y = - 8x + 5

y = (-8x + 5) / 4

y = - 2x + 5/4

The slope of the line we want is - 2.

Two lines are perpendicular if the slope of the first line times the slope of the second line produces a product of negative one.

Since our slope is - 2, we know that - 2 times 1/2 yields - 1.

The slope of the line perpendicular is 1/2.