Ask Question
17 January, 04:55

Two boys, Shawn and Curtis, went for a walk. Shawn began walking 20 seconds earlier than Curtis. Shawn walked at a speed of 5 feet per second. Curtis walked at a speed of 6 feet per second. For how many seconds had Sean been walking at the moment on the two boys had walked exactly the same distance?

+4
Answers (1)
  1. 17 January, 05:11
    0
    Distance = speed * time

    for curtis d = st = 6t (where t is the time that he walks)

    sean walks 20 seconds longer than curtis so we have the equation

    d = s (t+20) = 5 (t+20)

    as the distances are the same we have

    So sean has walked 100+20 = 2

    6t = 5 (t+20)

    6t = 5t + 100

    t = 100

    so Sean walks 120 seconds when they had both walked the same distance.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Two boys, Shawn and Curtis, went for a walk. Shawn began walking 20 seconds earlier than Curtis. Shawn walked at a speed of 5 feet per ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers