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22 September, 23:22

Find three consecutive integers such that three times the third is the same as 2 les than the sum of the first and second

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  1. 23 September, 00:35
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    Let the integers be x, x+1 and x+2.

    Thus, 3 (x + 2) = (x + x + 1) - 2

    Then 3x + 6 = 2x + 1 - 2, or 3x + 6 = 2x - 1

    Solving for x, x = - 7.

    First number is - 7

    Second one is - 6

    Third one is - 5
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