In a shipment of 58 vials, only 13 do not have hairline cracks. if you randomly select 4 vials from the shipment, what is the probability that all 4 of the selected vials have hairline cracks? g

For this problem, we use the repeated trials equation:

P = n!/r! (n-r) !*p^ (n-r) * q^r

where

P is the total probability of having r successful trials out of the total n trials. p is equal to 13/58, while q is equal to 1 - 13/58.

P = 4!/4! (4-4) ! * (13/58) ^ (4-4) * (1 - 13/58) ^4

P = 0.362 or 36.2%