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14 April, 22:36

Find the indicated values, where g (t) = t^2-1 and f (x) = 1+x g (f (3) - 2f (1))

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  1. 15 April, 01:21
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    F (3) = 1 + 3 = 4

    f (1) = 1 + 1 = 2

    g (f (3) - 2f (1)) = g (4 - 2*2) = g (4 - 4) = g (0) = 0^2 - 1 = - 1
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