A system of equations is shown below.

2x-y=5

x+3y=0

Which statement is true regarding this system?

A - to solve the system, multiply the second equation by 2 and then add the result to the first equations

B - to solve the system, multiply the first equation by 3 and then add the result to the second equation.

C - the system has no solution since the second equation is equal to 0.

D - the system has infinitely many solutions since the second equation is equal to 0

Question

Mathematics

Guest

7 April, 01:33

A system of equations is shown below.

2x-y=5

x+3y=0

Which statement is true regarding this system?

A - to solve the system, multiply the second equation by 2 and then add the result to the first equations

B - to solve the system, multiply the first equation by 3 and then add the result to the second equation.

C - the system has no solution since the second equation is equal to 0.

D - the system has infinitely many solutions since the second equation is equal to 0

+5

Answers (1)

Know the Answer?

Larissa Caldwell · Answer 1

B - to solve the system, multiply the first equation by 3 and then add the result to the second equation.

I:2x-y=5

II:x+3y=0

I*3=6x-3y=15

I*3+II: 6x-3y+x+3y=15+0

7x=15

x=15/7

insert x=15/7 into II:

(15/7) + 3y=0

3y=-15/7

y=-5/7