For what values of x will (x, y) be a solution of the system of equations below: y = x2 + 3x - 3 2x - 1 = y

hello:

y = x2 + 3x - 3 ... (1)

2x - 1 = y ... (2)

subsct in (1):

2x-1 = x² + 3x - 3

x² + x - 2 = 0

(x+2) (x-1) = 0

x+2=0 or x-1 = 0

x=-2 or x=1

if : x = - 2 y = 2 (-2) - 1 = - 2

if : x = 1 y = 2 (1) - 1 = 1

values of x will (x, y) be a solution of the system : (-2,-2), (1,1)