Solve the simultaneous equation, 5x=2y+1 2x-3y+4+0

Hello,

I suppose the 2th equation is 2x-3y+4=0

5x-2y=1 ... |*2 | * 3

2x-3y=-4 ... | * (-5) | * - 2

==> - 4y+15y=2+20==>11y=22==>y=2

and 15x-4x=3+8 = = >11x=11 = = >x=1

Proof:

5*1=? 2*2+1 yes

2*1-3*2+4=? 0 yes (linear combinaison method)