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11 January, 06:19

Solve the simultaneous equation, 5x=2y+1 2x-3y+4+0

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  1. 11 January, 07:20
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    Hello,

    I suppose the 2th equation is 2x-3y+4=0

    5x-2y=1 ... |*2 | * 3

    2x-3y=-4 ... | * (-5) | * - 2

    ==> - 4y+15y=2+20==>11y=22==>y=2

    and 15x-4x=3+8 = = >11x=11 = = >x=1

    Proof:

    5*1=? 2*2+1 yes

    2*1-3*2+4=? 0 yes (linear combinaison method)
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