A parabola has a minimum value of 0, a y-intercept of 4, and an axis of symmetry at x = - 2

Since the minimum value is 0 and axis of symmetry is - 2 this means that the vertex is at - 2,0 now with the y intercept of 4. You can now plug the values into Vertex form which will be y=a (x-h) ^2+k. a being the shrink or stretch of the parabola, h being the x value of the vertex, and k being the y value of the vertex. with all of that plugged in it should look like y = (x+2) ^2. You can check this equation by plugging in 0 as x which should find the y intercept of 4. So it should then look like y = (0+2) ^2 - > y = (2) ^2 - > y=4