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24 April, 05:34

Factor completely 2x3 + x2 - 18x - 9

A. (x2-9) (2x+1)

B. (x-3) (x+3) (2x-1)

C. (x-3) (x+3) (2x+1)

D. (2x-3) (2x+3) (x-1)

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Answers (2)
  1. 24 April, 08:21
    0
    Option C is the answer
  2. 24 April, 08:42
    0
    Factor the following:

    2 x^3 + x^2 - 18 x - 9

    Factor terms by grouping. 2 x^3 + x^2 - 18 x - 9 = (2 x^3 + x^2) + (-18 x - 9) = x^2 (2 x + 1) - 9 (2 x + 1):

    x^2 (2 x + 1) - 9 (2 x + 1)

    Factor 2 x + 1 from x^2 (2 x + 1) - 9 (2 x + 1):

    (2 x + 1) (x^2 - 9)

    x^2 - 9 = x^2 - 3^2:

    (2 x + 1) (x^2 - 3^2)

    Factor the difference of two squares. x^2 - 3^2 = (x - 3) (x + 3):

    Answer: (x - 3) (x + 3) (2 x + 1) thus the Answer is C.
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