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20 May, 19:38

A person whose height is 6 feet is walking away from the base of a streetlight along a straight path at a rate of 4 feet per second. If the height of a streetlight is 15 feet, what is the rate at which a person's shadow is lengthening?

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  1. 20 May, 21:12
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    Let the distance from the pole be x and the length of the shadow be s. Using the law of similar triangles, we have:

    s/6 = (x+s) / 15

    thus

    5s=2x+2s

    3s=2x

    hence

    ds/dt=2/3 dx/dt

    but

    dx/dt=4 ft per second

    hence

    ds/dt=2/3*4=8/3
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