Ask Question
21 May, 19:01

Curtis build a dog house with base shaped like a cube and a roof shaped like a pyramid. The cube has an edge lenght of 3 1/2 feet. The height of the pyramid is 5 feet. Find the volume of the doghouse rounded to the nearest tenth.

+5
Answers (1)
  1. 21 May, 22:11
    0
    The volume of the cube is:

    V1 = L ^ 3

    Where,

    L: length of the sides of the cube.

    Substituting we have:

    V1 = (3 + 1/2) ^ 3

    V1 = 42,875 feet ^ 3

    The volume of the pyramid is:

    V2 = ((Ab) * (h)) / (3)

    Where,

    Ab: base area

    h: height

    Substituting we have:

    V2 = (((3 1/2) * (3 1/2)) * (5)) / (3)

    V2 = 20.41666667 feet ^ 3

    The volume of the house is the sum of both volumes:

    V1 + V2 = 42,875 feet ^ 3 + 20.41666667 feet ^ 3

    V1 + V2 = 63.29166667 feet ^ 3

    Nearest tenth:

    V1 + V2 = 63.3 feet ^ 3

    Answer:

    The volume of the doghouse rounded to the nearest tenth is:

    V1 + V2 = 63.3 feet ^ 3
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Curtis build a dog house with base shaped like a cube and a roof shaped like a pyramid. The cube has an edge lenght of 3 1/2 feet. The ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers