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2 December, 05:04

The length of a rectangle is 2 cm longer than its width if the perimetier of the rectangle is 44cm, find its area

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  1. 2 December, 05:57
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    L=w+2 and 2w+2l=44

    substitute equation for length in perimeter equation

    2w+2 (w+2) = 44

    2w+2w+4=44

    4w+4=44

    4w=40

    w=10

    substitute width into length equation to get length

    l=10+2

    l=12

    a=lw

    a=12*10

    a=120 cm^2
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