If p (q-r) x^2 + q (r-p) x + r (p-q) has equal roots, then, 2/q=?

a) p + 1/r c) p+r

b) 1/p + r d) 1/p + 1/r

Question

Addyson Buck

30 June, 00:38

+3

Answers (1)

Know the Answer?

Cullen Riley · Answer 1

The answer is d) 1/p + 1/r.

Solution to this is,

[r (p-q) / p (q-r) ]=1

pr-qr=pq-pr

2pr=pq+qr

2pr/pqr = (pq+qr) / pqr

2/q=1/r+1/p

If p (q-r) x^2 + q (r-p) x + r (p-q) has equal roots, then, 2/q=?a) p + 1/r c) p+rb) 1/p + r d) 1/p + 1/r