Ask Question
25 November, 09:25

A triangle has an area of 1102 m², and two of the sides of the triangle have lengths 60 m and 56 m. find the angle included by these two sides.

+3
Answers (1)
  1. 25 November, 12:33
    0
    A = (1/2) * a*b*sin (C)

    1102 m^2 = (1/2) * (60 m) * (56 m) * sin (C)

    2*1102 / (60*56) = 551/840 = sin (C)

    C = arcsin (551/840) ≈ 41°
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A triangle has an area of 1102 m², and two of the sides of the triangle have lengths 60 m and 56 m. find the angle included by these two ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers