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5 March, 16:16

Given a triangle with b = 7 c = 3 and A = 37 degrees, what is the length of a?

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  1. 5 March, 16:22
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    Using cosine rule a^2 = b^2 + c^2 - 2bc cos A = 7^2 + 3^2 - (2 x 7 x 3) cos 37 = 49 + 9 - 42cos 37 = 58 - 33.54 = 24.46

    a = sqrt (24.46) ≈ 5
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