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29 November, 19:17

Solve the equation sin theta =.3 to the nearest tenth. Use the restrictions 90 < theta <180

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  1. 29 November, 20:26
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    Sinα=3/10

    α=arcsin (3/10) °

    α≈17.5°

    But since we are restricted to 90°<α<180° the angle must lie in the second quadrant so:

    α≈ (180-17.5) °

    α≈162.5°
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