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Today, 13:15

Find all solutions to x^3-2x^2-3x=0 in Z12

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  1. Today, 13:24
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    Solutions can be found by factoring:

    x^3-2x^2-3x

    =x (x^2-2*x-3)

    =x (x+1) (x-3)

    By the zero product theorem,

    x=0, or

    (x+1) = 0 = > x=-1, or

    (x-3) = 0 = > x=3

    Therefore the solutions are

    {-1,0,3}
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