The sun and a planet with a period of 5 years would have a distance of

To solve the problem shown above you must apply the proccedure shown below:

1. You must apply the Kepler's third law, as below:

(T1/T2) ² = (R1/R2) ³

T1 and T2 are the orbital periods. (T1=1 year; T2=5 years)

R1 and R2 are the orbital radius. (R1=1 Astronomical unit)

2. Now, you must substitute the values shown above into the formula and clear R2:

(1/5) ² = (1/R2) ³

1/25=1/R2³

R2³/25=1

R2³=25

R2=∛25

R2=2.92 AU

Therefore, the answer is: 2.92 AU