A carpenter is making tables (x) and chairs (y). Each table takes 5 hours to make and is sold for $100 and each chair takes 3 hours to make and is sold for $30. His goal each week is to make more than $500 from selling his tables and chairs and work no more than 40 hours. Which combination of tables and chairs would maximize his profit?

Question options:

a / 8 tables and 0 chairs

b / 2 tables and 10 chairs

c / 4 tables and 3 chairs

d / 5 tables and 0 chairs

Question

Mathematics

Guest

10 December, 07:45

A carpenter is making tables (x) and chairs (y). Each table takes 5 hours to make and is sold for $100 and each chair takes 3 hours to make and is sold for $30. His goal each week is to make more than $500 from selling his tables and chairs and work no more than 40 hours. Which combination of tables and chairs would maximize his profit?

Question options:

a / 8 tables and 0 chairs

b / 2 tables and 10 chairs

c / 4 tables and 3 chairs

d / 5 tables and 0 chairs

+5

Answers (1)

Know the Answer?

Rodney Pitts · Answer 1

X = tables and y = chairs

5x + 3y < = 40

100x + 30y > 500

well ... 8 tables and 0 chairs ... he will be at 40 hrs and make $ 800 ... so I believe ur answer is A