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28 November, 18:55

7 A triangle is right-angled if the sides are a = m2 - n2, b = 2mn and c = m2 + n2 where m and n are positive integers, and m > n.

Show that this is true by substituting into the equation c2 = a2 + b2.

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  1. 28 November, 21:10
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    The general formula for the sides of right triangle is

    a² + b² = c²

    Subtitute the equation of a and b to the formula a² + b², evaluate if the answer will be the same as the equation of c²

    a² + b²

    = (m² - n²) ² + (2mn) ²

    = (m² - n²) (m² - n²) + (2mn) (2mn)

    = (m⁴ - 2m²n² + n⁴) + 4m²n²

    = m⁴ + 2m²n² + n⁴

    Factorize the result

    m⁴ + 2m²n² + n⁴

    = (m² + n²) (m² + n²)

    = (m² + n²) ²

    = c²

    It's proven by the formula that c² = (m² + n²) ²

    so the c will be m² + n²
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