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16 June, 17:03

Ray HX is an angle bisector of angle THV, m angle THX = (6x+5) degrees

and m angle XHV = (8x-15) degrees.

What is m angle THX

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  1. 16 June, 19:03
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    M∠THX = 65°.

    Since HX is an angle bisector, m∠THX = m∠XHV.

    6x+5=8x-15

    We can't have a variable on both sides of the equation, so we cancel 6x by subtracting it from both sides:

    6x+5-6x=8x-15-6x

    5=2x-15

    Cancel 15 by adding to both sides:

    5+15=2x-15+15

    20=2x

    Cancel 2 by dividing both sides by 2:

    20/2 = 2x/2

    10=x

    Substitute this into the expression for ∠THX:

    6x+5=6 (10) + 5=65
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