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11 March, 06:41

For y=4*+2x^2-x^3, show how to find the value of y when x=2

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  1. 11 March, 10:13
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    Just put two instead of x like y = 4.2+2.4 (2 squared) - 8 (cubic 2) that gives y = 8+8-8 = 8 then y equals 8
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