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21 April, 11:45

The decay of 192 mg of an isotope is given by A (t) = 192e-0.015t, where t is time in years. Find the amount left after 55 years. Round your answer to the nearest whole number.

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  1. 21 April, 14:51
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    This is a typical radioactive decay problem which uses the general form:

    A = A0e^ (-kt)

    So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:

    A = 192e^ (-0.015*55)

    A = 84 mg
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