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21 October, 23:49

A rock is dropped off a cliff that is 138 m tall. How long will it take to hit the ground? What is the rock's final velocity?

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  1. 22 October, 02:36
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    Y = (1/2). g, t² + v₀. t, where:

    y = distance = 138 m

    g = 9.8 m/s² (gravity)

    v₀ = initial speed = 0

    138 = (1/2) (9.8). t² + 0 →138 = 4.9. t² and t² = 138/4.9 = 28.16 and t = 5.3 s

    Final speed V (final) = V (initial) + gt

    V (final) = 0 + 9.8 (5.3) = 51.94 m/s ≈ 52 m/s
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