A piggy bank contains dimes and quarters. There are a total of 64 coins in the bank with a total value of $10.30. How many of each coin were in yhe piggy bank?

This is the concept of simultaneous equations. Let the number of dimes be x and that of quarters by y.

1 quarter = $0.25

1 dime=$0.1

Total number of coins in piggy bank

x+y=64

thus

x=64-y ... i

Total amount will be:

0.1x+0.25y=10.30 ... ii

substituting i in ii and solve for y we get:

0.1 (64-y) + 0.25y=10.30

6.4-0.1y+0.25y=10.30

0.15y=10.30-6.4

0.15y=3.9

y=3.9/0.15

y=26

hence:

x=64-y=64-26=38

Therefore we conclude that there are 38 dimes and 26 quarters