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25 July, 08:02

Find an equation for the plane that is perpendicular to the line l (t) = (2, 0, 9) t + (3, - 1, 1) and passes through (9, - 1, 0).

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  1. 25 July, 09:57
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    The plane will have its normal vector equal to the direction vector of the line (2, 0, 9). Its equation is

    2x + 9z = (2, 0, 9) • (9, - 1, 0)

    2x + 9z = 18
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