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9 October, 18:56

If you have a rectangular rug whose perimeter is 26 feet and the length is three feet more than the width, what are the dimensions of the rug? (P=2w+2l)

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  1. 9 October, 22:18
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    You have the lenght that is 3w, so lenght is the third part and the width the first part.

    You assign the value 3 to l and the value 1 to w

    Of course, you have to do the "semiperimeter" or you'll get double sides.

    Semiperimeter = 26/2 = 13 ft.

    You sum the parts

    3+1 = 4

    13/4 = 3,25 ft. (1 part)

    3,25*1 = 3,25 ft. (Widht)

    3,25*3 = 9,75 ft. (Lenght)

    You can solve it even as an equation

    You put x the lenght, the width is 3x

    x+3x = 13

    4x = 13

    x = 3,25

    w = 3*3,25 = 9,75
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