15x+31y=-3 x=-y+3

15x + 31y = - 3

x = - y + 3

To solve this system, substitute - y + 3 into 15x + 31y = - 3 for x, and solve algebraically for y.

15x + 31y = - 3

15 (-y + 3) + 31y = - 3

-15y + 45 + 31y = - 3

16y + 45 = - 3

16y = - 48

y = - 3

Substitute - 3 for y into either of the original equations and solve algebraically for x.

x = - y + 3

x = - (-3) + 3

x = 3 + 3

x = 6

Finally, substitute both x - and y-values into both original equations to check work.

15x + 31y = - 3

15 (6) + 31 (-3) = - 3

90 + (-93) = - 3

-3 = - 3

6 = - (-3) + 3)

6 = 3 + 3

6 = 6

Answer:

x = 6

y = - 3

(6, - 3)