What is the equation of a parabola with a vertex at (0, 0) and a directrix x = - 4?

A. y equals negative one-sixteenth times x squared

B. x equals negative one-sixteenth times y squared

C. x equals one-sixteenth times y squared

D. y equals one-sixteenth times x squared

Question

Mathematics

Beau Koch

3 September, 17:15

What is the equation of a parabola with a vertex at (0, 0) and a directrix x = - 4?

A. y equals negative one-sixteenth times x squared

B. x equals negative one-sixteenth times y squared

C. x equals one-sixteenth times y squared

D. y equals one-sixteenth times x squared

+4

Answers (1)

Know the Answer?

Abbigail Mendez · Answer 1

The general form for this is y^2 = 4ax where a = focus

the directrix is same distabce behind the vertex as focus is in font so focus a = 4

so we have y^2 = 16 x

or

x = (1/16) y^2

Its C

What is the equation of a parabola with a vertex at (0, 0) and a directrix x = - 4?A. y equals negative one-sixteenth times x squaredB. x equals negative one-sixteenth times y squaredC. x equals one-sixteenth times y squaredD. y equals one-sixteenth times x squared

What is the equation of a parabola with a vertex at (0, 0) and a directrix x = - 4?

A. y equals negative one-sixteenth times x squared

B. x equals negative one-sixteenth times y squared

C. x equals one-sixteenth times y squared

D. y equals one-sixteenth times x squared