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16 September, 13:08

Of 259 employees selected randomly from one company, 9.27% of them commute by carpooling. use this data to construct a 90% confidence interval for the true percentage of all employees of the company who carpool.

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  1. 16 September, 14:16
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    B. 14.4% < p < 22.9%

    std error = sqrt (.1867 * (1=.1867) / 225) = 0.025978

    t critical value for 224 degrees of freedom = 1.65168

    .1867-1.65168*0.025978 < = true proportion < =.1867+1.65168*0.025978

    .143793 < = true proportion < =.2299607
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