Ask Question
1 October, 23:55

How many positive three-digit integers have the hundreds digit equal to 7 and the units digit equal to 1?

+4
Answers (1)
  1. 2 October, 02:09
    0
    This is an example of a permutation problem.

    Since there are three digits, the total number of possibilities would be:

    total number of possibilities = (amount of numbers that can take up hundreds place) * (amount of numbers that can take up tens place) * (amount of numbers that can take up ones place)

    It is given that there is only one number that can take up the hundreds and ones place, 7 and 1 respectively. For the tens place, there are ten numbers that can take this place (0 to 9), therefore:

    total number of possibilities = 1 * 10 * 1

    total number of possibilities = 10

    There are 10 positive three - digit integers.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “How many positive three-digit integers have the hundreds digit equal to 7 and the units digit equal to 1? ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers