In this particular arithmetic sequence, a8 = 45 and a16 = 93. What is the value of a24?

Hint: an = a1 + d (n - 1), where a1 is the first term and d is the common difference.

a24 = 141

a24 = 106

a24 = 111

a24 = 147

A24 = 141,

using equation,

an = a1 + (n-1) d,

a8 = a + 7d = 45

a16 = a + 15d = 93

solve simultaneously for values a and d, where a = 3, and d = 6.

therefore, inserting values into a24 eqn, where

a24 = 3 + (24-1) (6) = 141.